Regular Expressions
Regular expressions, commonly abbreviated as regex, form a language for string matching, enabling operations to search, match, and manipulate text based on specific patterns or rules.
Online Interpreter: Regular Expressions 101
Core Syntax
Metacharacters
Regex provides metacharacters with specific meanings, making it convenient to define patterns:
.: any single character except a newline charactere.g.,
M.\.matches "Mr." and "Ms.", but not "Mrs." (\escapes the metacharacter.).[ ]: a character set matching any character within the bracketse.g.,
[aeiou]matches any vowel.\d: any digit, equivalent to[0-9]e.g.,
\d\d\dsearches for "170" in "CS170".\D: any character that is not a digit, equivalent to[^0-9]e.g.,
\D\Dsearches for "kg" in "100kg".\s: any whitespace character, equivalent to[ \t\n\r\f\v]e.g.,
\ssearches for the space " " in "Hello World".\S: any character that is not a whitespace character, equivalent to[^ \t\n\r\f\v]e.g.,
\Ssearches for "H" in " Hello".\w: any word character (alphanumeric or underscore), equivalent to[A-Za-z0-9_]e.g.,
\w\wsearches for "1K" in "$1K".\W: any character that is not a word character, equivalent to[^A-Za-z0-9_]e.g.,
\Wsearches for "!" in "Hello!".\b: a word boundary matching the position between a word character and a non-word charactere.g.,
\bis\bmatches "is", but does not match "island" nor searches for "is" in "basis".
Repetitions
Repetitions allow you to define complex patterns that can match multiple occurrences of a character or group of characters:
*: the preceding character or group appears zero or more timese.g.,
\d*matches "90" in "90s" as well as "" (empty string) in "ABC".+: the preceding character or group appears one or more timese.g.,
\d+matches "90" in "90s", but no match in "ABC".?: the preceding character or group appears zero or once, making it optionale.g.,
https?matches both "http" and "https".{m}: the preceding character or group appears exactlymtimese.g.,
\d{3}is equivalent to\d\d\d.{m,n}: the preceding character or group appears at leastmtimes but no more thanntimese.g.,
\d{2,4}matches "12", "123", "1234", but not "1" or "12345".{m,}: the preceding character or group appears at leastmtimes or moree.g.,
\d{2,}matches "12", "123", "1234", and "12345", but not "1".By default, matches are "greedy" such that patterns match as many characters as possible
e.g.,
<.+>matches the entire string of "<Hello> and <World>".Matches become "lazy" by adding
?after the repetition metacharacters, in which case, patterns match as few characters as possiblee.g.,
<.+?>matches "<Hello>" in "<Hello> and <World>", and searches for "<World>" in the text.
Groupings
Grouping allows you to treat multiple characters, subpatterns, or metacharacters as a single unit. It is achieved by placing these characters within parentheses ( and ).
|: a logical OR, referred to as a "pipe" symbol, allowing you to specify alternativese.g.,
(cat|dog)matches either "cat" or "dog".( ): a capturing group; any text that matches the parenthesized pattern is "captured" and can be extracted or used in various wayse.g.,
(\w+)@(\w+.\w+)has two capturing groups,(\w+)and(\w+.\w+), and matches email addresses such as "john@emory.edu" where the first and second groups capture "john" and "emory.edu", respectively.(?: ): a non-capturing group; any text that matches the parenthesized pattern, while indeed matched, is not "captured" and thus cannot be extracted or used in other wayse.g.,
(?:\w+)@(\w+.\w+)has one non-capturing group(?:\w+)and one capturing group(\w+.\w+). It still matches "john@emory.edu" but only captures "emory.edu", not "john".\num: a backreference that refers back to the most recently matched text by thenum'th capturing group within the same regexe.g.,
(\w+) (\w+) - (\2), (\1)has four capturing groups, where the third and fourth groups refer to the second and first groups, respectively. It matches "Jinho Choi - Choi, Jinho" where the first and fourth groups capture "Jinho" and the second and third groups capture "Choi".You can nest groups within other groups to create more complex patterns
e.g.,
(\w+.(edu|org))has two capturing groups, where the second group is nested in the first group. It matches "emory.edu" or "emorynlp.org", where the first group captures the entire texts while the second group captures "edu" or "org", respectively.
Assertions
Assertions define conditions that must be met for a match to occur. They do not consume characters in the input text but specify the position where a match should happen based on specific criteria.
A positive lookahead assertion
(?= )checks that a specific pattern is present immediately after the current positione.g.,
apple(?=[ -]pie)matches "apple" in "apple pie" or "apple-pie", but not in "apple juice".A negative lookahead assertion
(?! )checks that a specific pattern is not present immediately after the current positione.g.,
do(?!(?: not|n't))matches "do" in "do it" or "doing", but not in "do not" or "don't".A positive look-behind assertion
(?<= )checks that a specific pattern is present immediately before the current positione.g.,
(?<=\$)\d+matches "100" in "$100", but not in "100 dollars".A negative look-behind assertion
(?<! )checks that a specific pattern is not present immediately before the current positione.g.,
(?<!not )(happy|sad)searches for "happy" in "I'm happy", but does not search for "sad" in "I'm not sad".^asserts that the pattern following the caret must match at the beginning of the texte.g.,
notsearches for "not" in "note" and "cannot", whereas^notmatches "not" in "note" but not in "cannot".$asserts that the pattern preceding the dollar sign must match at the end of the texte.g.,
not$searches for "not" in "cannot" but not in "note".
Functions
Python provides several functions to make use of regular expressions.
match()
Let us create a regular expression that matches "Mr." and "Ms.":
import re
re_mr = re.compile(r'M[rs]\.')
m = re_mr.match('Mr. Wayne')
print(m)
if m: print(m.start(), m.end())L3: Create a regular expression
re_mr(compile()). Note that a string indicated by anrprefix is considered a regular expression in Python.r'M'matches the letter "M".r'[rs]'matches either "r" or "s".r'\.' matches a period (dot).
L4: Try to match
re_mrat the beginning of the string "Mr. Wayne" (match()).L6: Print the value of
m. If matched, it prints the match object information; otherwise,misNone; thus, it prints "None".
<re.Match object; span=(0, 3), match='Mr.'>
0 3group()
Currently, no group has been specified for re_mr:
print(m.groups())L1: groups()
()Let us capture the letters and the period as separate groups:
re_mr = re.compile(r'(M[rs])(\.)')
m = re_mr.match('Ms.')
print(m)
print(m.group())
print(m.groups())
print(m.group(0), m.group(1), m.group(2))L1: The pattern
re_mris looking for the following:1st group: "M" followed by either "r" or 's'.
2nd group: a period (".")
L2: Match
re_mrwith the input string "Ms".L5: Print the entire matched string (group()).
L6: Print a tuple of all captured groups (groups()).
L7: Print specific groups by specifying their indexes. Group 0 is the entire match, group 1 is the first capture group, and group 2 is the second capture group.
<re.Match object; span=(0, 3), match='Ms.'>
Ms.
('Ms', '.')
Ms. Ms .If the pattern does not find a match, it returns None.
m = RE_MR.match('Mrs.')
print(m)Nonesearch()
Let us match the following strings with re_mr:
s1 = 'Mr. and Ms. Wayne are here'
s2 = 'Here are Mr. and Ms. Wayne'
print(re_mr.match(s1))
print(re_mr.match(s2))<re.Match object; span=(0, 3), match='Mr.'>
Nones1 matches "Mr." but not "Ms." while s2 does not match any pattern. It is because the match() function matches patterns only at the beginning of the string. To match patterns anywhere in the string, we need to use search() instead:
print(re_mr.search(s1))
print(re_mr.search(s2))<re.Match object; span=(0, 3), match='Mr.'>
<re.Match object; span=(9, 12), match='Mr.'>findall()
The search() function matches "Mr." in both s1 and s2 but still does not match "Ms.". To match them all, we need to use the findall() function:
print(re_mr.findall(s1))
print(re_mr.findall(s2))[('Mr', '.'), ('Ms', '.')]
[('Mr', '.'), ('Ms', '.')]finditer()
While the findall() function matches all occurrences of the pattern, it does not provide a way to locate the positions of the matched results in the string. To find the locations of the matched results, we need to use the finditer() function:
ms = re_mr.finditer(s1)
for m in ms: print(m)
ms = re_mr.finditer(s2)
for m in ms: print(m)<re.Match object; span=(0, 3), match='Mr.'>
<re.Match object; span=(8, 11), match='Ms.'>
<re.Match object; span=(9, 12), match='Mr.'>
<re.Match object; span=(17, 20), match='Ms.'>sub()
Finally, you can replace the matched results with another string by using the sub() function:
print(re_mr.sub('Dr.', 'I met Mr. Wayne and Ms. Kyle.'))I met Dr. Wayne and Dr. Kyle.Tokenization
Finally, let us write a simple tokenizer using regular expressions. We will define a regular expression that matches the necessary patterns for tokenization:
def tokenize(text: str) -> list[str]:
re_tok = re.compile(r'([",.]|\s+|n\'t)')
tokens, prev_idx = [], 0
for m in re_tok.finditer(text):
t = text[prev_idx:m.start()].strip()
if t: tokens.append(t)
t = m.group().strip()
if t:
if tokens and tokens[-1] in {'Mr', 'Ms'} and t == '.':
tokens[-1] = tokens[-1] + t
else:
tokens.append(t)
prev_idx = m.end()
t = text[prev_idx:]
if t: tokens.append(t)
return tokensL2: Create a regular expression to match delimiters and a special case:
Delimiters:
',','.', or whitespaces ('\s+').The special case:
'n't'(e.g., "can't").
L3: Create an empty list
tokensto store the resulting tokens, and initializeprev_idxto keep track of the previous token's end position.L5: Iterate over matches in
textusing the regular expression pattern.L6: Extract the substring between the previous token's end and the current match's start, strip any leading or trailing whitespace, and assign it to
t.L7: If
tis not empty (i.e., it is not just whitespace), add it to thetokenslist.L8: Extract the matched token from the match object strip any leading or trailing whitespace, and assign it to
t.L10: If
tis not empty (i.e., the pattern is matched):L11-12: Check if the previous token in
tokensis "Mr" or "Ms" and the current token is a period ("."), in which case, combine them into a single token.L13-14: Otherwise, add
ttotokens.
L18-19: After the loop, there might be some text left after the last token. Extract it, strip any leading or trailing whitespace, and add it to
tokens.
Test cases for the tokenizer:
text = 'Mr. Wayne isn\'t the hero we need, but "the one" we deserve.'
print(tokenize(text))
text = 'Ms. Wayne is "Batgirl" but not "the one".'
print(tokenize(text))['Ms.', 'Wayne', 'is', '"', 'Batgirl', '"', 'but', 'not', '"', 'the', 'one', '"']
['Ms.', 'Wayne', 'is', '"', 'Batgirl', '"', 'but', 'not', '"', 'the', 'one', '"', '.']Q10: What are the benefits and limitations of using regular expressions for tokenization vs. the rule-based tokenization approach discussed in the previous section?
References
Source: regular_expressions.py
Regular Expression, Kuchling, HOWTOs in Python Documentation
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